A ball is thrown vertically upward with a velocity of 20 m/s from the top of a building. The height of the building is 25 m. How long will it take for the ball to reach the ground? (g = 10 m/s²)

Two balls are projected simultaneously from the top of a tower, one vertically upward and the other vertically downward with the same speed. By the time the first ball reaches the ground, the ratio of displacements of the two balls is:

The position of a particle is given by x = 3t³ + 7t² + 5t + 8 m. Its acceleration at t = 1 s is:

A projectile is thrown at angle 60° with horizontal with speed 20 m/s. Its range is: (g = 10 m/s²)

A body covers 100 m in the first 10 s and next 150 m in the next 10 s. The velocity at the end of 20 s is:

The time of flight of a projectile is 10 s and its range is 500 m. Maximum height attained is: (g = 10 m/s²)

A body starts from rest and travels a distance of 200 m in 10 s. The acceleration is:

A stone is dropped from a 45 m high tower. Time to reach ground: (g = 10 m/s²)

Two projectiles A and B are thrown with same speed but at angles 30° and 60° with horizontal. Their ranges are:

A car accelerates from rest at 2 m/s² for 10 s, then moves at constant velocity for 10 s. Total distance covered: