Jee Practice Mathematics Trigonometry

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Trigonometry — JEE Practice

45 practice questions across 3 topics. Filter by difficulty, solve topic-wise MCQs, and review detailed solutions.

3 Topics45 Questions

Trigonometric Functions & Identities(15 Qs)

easy (5)

Q1sin²θ + cos²θ =Q2sin 30° =Q3tan θ = sin θ / cos θ. If θ = 45°, tan 45° =Q4Period of sin x is:Q5cos(-θ) =

medium (5)

Q1sin 2θ =Q2cos 2θ =Q3General solution of sin θ = sin α is:Q4sin A + sin B =Q5In a triangle, a/sin A = b/sin B = c/sin C is called:

hard (5)

Q1The value of cos 20° cos 40° cos 80° =Q2If tan(A+B) = 3 and tan A = 2, then tan B =Q3cos⁻¹(cos(7π/6)) =Q4In △ABC, cos A = (b²+c²-a²)/(2bc) is the:Q5If sin⁻¹x + cos⁻¹x = π/2, then sin⁻¹(3/5) + cos⁻¹(3/5) =

Ratios, Identities & Equations(15 Qs)

easy (5)

Q1sin²θ + cos²θ equals:Q2sin(90° - θ) equals:Q3The value of sin 30° is:Q4tan θ = sin θ / cos θ. If sin θ = 3/5 and θ is in first quadrant, cos θ =Q5The period of sin x is:

medium (5)

Q1sin(A+B) =Q2cos 2θ can be written as:Q32 sinA cosA =Q4General solution of sin x = 0 is:Q5The range of sin⁻¹(x) is:

hard (5)

Q1sin⁻¹x + cos⁻¹x = (for |x| ≤ 1):Q2In triangle ABC, a/sinA = b/sinB = c/sinC = 2R. This is:Q3cos A = (b²+c²-a²)/(2bc) is:Q4tan⁻¹(1) + tan⁻¹(2) + tan⁻¹(3) =Q5The maximum value of a sinθ + b cosθ is:

Properties of Triangles(15 Qs)

easy (5)

Q1Sum of angles of a triangle is:Q2Area of triangle = ½ × base × height. Using sides a, b and included angle C:Q3The circumradius R of a triangle with side a opposite angle A is:Q4For an equilateral triangle with side a, each angle is:Q5In a right triangle, c² = a² + b² where c is:

medium (5)

Q1Hero's formula: Area = √(s(s-a)(s-b)(s-c)) where s =Q2The inradius r of a triangle is:Q3In triangle ABC, if A = 90°, then a² =Q4The median from vertex A to side BC has length:Q5tan(A/2) = r/(s-a) where r is inradius. This is called:

hard (5)

Q1The nine-point circle radius equals:Q2Euler's formula for distance between circumcentre O and incentre I: OI² =Q3In a triangle, r₁ (exradius opposite to A) equals:Q4The Stewart's theorem states for cevian AD of length d to side BC = a, with BD=m, DC=n:Q5For an isosceles triangle with equal sides b=c, the circumradius R =

More Mathematics Chapters

Sets, Relations & Functions

15 Qs

Complex Numbers

15 Qs

Quadratic Equations

15 Qs

Permutations & Combinations

15 Qs

Binomial Theorem

15 Qs

Matrices & Determinants

15 Qs

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