Jee Practice Physics Thermodynamics

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Thermodynamics — JEE Practice

45 practice questions across 3 topics. Filter by difficulty, solve topic-wise MCQs, and review detailed solutions.

3 Topics45 Questions

Zeroth & First Law(15 Qs)

easy (5)

Q1The first law of thermodynamics is a statement of:Q2In an isothermal process, the temperature:Q3In an adiabatic process:Q4Work done in an isobaric process is:Q5Internal energy of an ideal gas depends only on:

medium (5)

Q1For an ideal gas in an isothermal process: PV = constant. The work done is:Q2In an adiabatic process for an ideal gas, PVᵞ = constant. The work done is:Q3The slope of an adiabatic curve on a PV diagram compared to an isothermal is:Q4In a cyclic process, the change in internal energy is:Q5One mole of an ideal gas at temperature T has internal energy:

hard (5)

Q1In a polytropic process PVⁿ = const, the specific heat is:Q2An ideal gas undergoes free expansion (into vacuum). After expansion:Q3A monoatomic ideal gas (1 mol) at 300K expands adiabatically to double volume. The final temperature is:Q4The work done by an ideal gas going from state A to B via two different paths:Q5In an adiabatic process, if volume is halved, pressure of a diatomic gas changes by factor:

Second Law & Heat Engines(15 Qs)

easy (5)

Q1Efficiency of a Carnot engine between temperatures T₁ (hot) and T₂ (cold) is:Q2According to the second law of thermodynamics:Q3A Carnot engine operating between 600K and 300K has efficiency:Q4The entropy of the universe in any natural process:Q5A refrigerator:

medium (5)

Q1The coefficient of performance (COP) of a Carnot refrigerator between T_cold and T_hot is:Q2An engine absorbs 1000 J from hot reservoir and rejects 600 J. Its efficiency is:Q3Which process has the maximum entropy change for heating from T₁ to T₂?Q4Two Carnot engines are in series: first between 600K and 400K, second between 400K and 300K. Combined efficiency:Q5The entropy change when 1 kg of ice at 0°C melts to water at 0°C (L = 3.33 × 10⁵ J/kg) is:

hard (5)

Q1The entropy of mixing two ideal gases (n₁ moles and n₂ moles) initially at same T and P is:Q2A heat engine takes Q₁ at T₁ and rejects Q₂ at T₂. For it to be reversible:Q3An irreversible engine between 800K and 300K absorbs 1000 J. The maximum possible work is:Q4The Clausius inequality states:Q5The entropy change of n moles of ideal gas going from (P₁,V₁,T₁) to (P₂,V₂,T₂) is:

Kinetic Theory of Gases(15 Qs)

easy (5)

Q1The average kinetic energy of a gas molecule is proportional to:Q2The rms speed of gas molecules is:Q3At absolute zero temperature, the kinetic energy of gas molecules is:Q4The pressure exerted by an ideal gas is due to:Q5For an ideal gas, PV = nRT. R is called:

medium (5)

Q1The ratio v_rms : v_avg : v_mp for a gas is:Q2Degrees of freedom for a diatomic molecule at room temperature:Q3The mean free path of gas molecules increases with:Q4For a monoatomic ideal gas, Cₚ/Cᵥ (γ) is:Q5Maxwell-Boltzmann distribution gives the probability of finding molecules with:

hard (5)

Q1The mean free path of an O₂ molecule (d = 3.6 × 10⁻¹⁰ m) at STP is approximately:Q2At high temperatures, a diatomic gas has γ =:Q3The rms speed of H₂ molecules at 300K (M = 2×10⁻³ kg/mol) is:Q4In the Maxwell speed distribution, the fraction of molecules with speed between v and v+dv is proportional to:Q5The pressure of a gas in terms of energy density (E/V) is:

More Physics Chapters

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Rotational Motion

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