Jee Practice Physics Current Electricity

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Current Electricity — JEE Practice

30 practice questions across 2 topics. Filter by difficulty, solve topic-wise MCQs, and review detailed solutions.

2 Topics30 Questions

Ohm's Law & Resistance(15 Qs)

easy (5)

Q1Ohm's law states:Q2The SI unit of resistance is:Q3Resistors in series have equivalent resistance:Q4Resistors in parallel have equivalent resistance:Q5The resistance of a wire is proportional to:

medium (5)

Q1A wire of resistance R is stretched to double its length. Its new resistance is:Q2Current density J is:Q3The drift velocity of electrons in a wire carrying current I (cross section A, n electrons per unit volume) is:Q4The temperature coefficient of resistance for metals is:Q5The power dissipated in a resistor is:

hard (5)

Q1A wire has resistance R. It is cut into n equal pieces and connected in parallel. The new resistance is:Q2The resistivity of a semiconductor:Q3In a balanced Wheatstone bridge (P/Q = R/S):Q4The internal resistance of a cell can be determined by measuring:Q5In a potentiometer, the sensitivity increases by:

Kirchhoff's Laws & Circuits(15 Qs)

easy (5)

Q1Kirchhoff's current law (KCL) states:Q2Kirchhoff's voltage law (KVL) states:Q3EMF of a cell is:Q4Terminal voltage of a cell under load is:Q5In a Wheatstone bridge, balance condition is:

medium (5)

Q1Two cells of EMF ε₁ and ε₂ (internal resistances r₁, r₂) in parallel give equivalent EMF:Q2Maximum power is transferred to an external resistance R when:Q3A meter bridge is a practical form of:Q4In a circuit with 2 cells in series (same polarity), the total EMF is:Q5A galvanometer can be converted to a voltmeter by adding:

hard (5)

Q1In a network, the number of independent KCL equations for n nodes is:Q2An infinite ladder network has each series element R and each shunt element R. The equivalent resistance is:Q3The sensitivity of a potentiometer is defined as:Q4A cell of EMF 2V and internal resistance 1Ω is connected to two 2Ω resistors in parallel. The current from the cell is:Q5In a Wheatstone bridge, if P = 100Ω, Q = 200Ω, R = 150Ω, then for balance S =:

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