Jee Practice Chemistry Mole Concept

Jee Practice Chemistry Mole Concept — Personalized JEE & NEET coaching by MindPeak Institute. Expert mentors, adaptive curriculum, 95% success rate.

MindPeak Institute offers personalized 1-on-1 JEE and NEET coaching with a 95% success rate. Our adaptive curriculum and dedicated mentors help students achieve their dream ranks.

JEE CoachingNEET CoachingAll CoursesJEE Practice QuestionsNEET Practice QuestionsJEE Previous Year QuestionsNEET Previous Year QuestionsFree Trial Class
MindPeak InstituteMINDPEAK
HomeJEE CoachingNEET Coaching
CoursesPricingStudy PlanBlogContact
HomeJEE PracticeMole Concept & Stoichiometry
🧪Chapter Practice

Mole Concept & Stoichiometry — JEE Practice

30 practice questions across 2 topics. Filter by difficulty, solve topic-wise MCQs, and review detailed solutions.

2 Topics30 Questions

Mole & Avogadro Number(15 Qs)

easy (5)

Q1One mole of any substance contains how many entities?Q2The molar mass of water (H₂O) is:Q3Number of moles = ?Q4At STP, 1 mole of an ideal gas occupies:Q5The empirical formula of glucose (C₆H₁₂O₆) is:

medium (5)

Q15.6 L of a gas at STP contains how many moles?Q2How many molecules are in 9 g of water?Q3The percentage of oxygen in Al₂O₃ is approximately:Q4If 2 moles of H₂ react with 1 mole of O₂, the limiting reagent when 3 mol H₂ and 1 mol O₂ are mixed:Q5Molarity of a solution is defined as:

hard (5)

Q1A compound has 40% C, 6.7% H, 53.3% O. Its empirical formula is:Q2100 mL of 0.1 M HCl is mixed with 100 mL of 0.1 M NaOH. The resulting solution pH is:Q3In the reaction 2KMnO₄ + 16HCl → 2KCl + 2MnCl₂ + 5Cl₂ + 8H₂O, the equivalent weight of KMnO₄ is:Q4The normality of 0.5 M H₂SO₄ is:Q5A mixture of NaHCO₃ and Na₂CO₃ weighing 1 g requires 12 mL of 0.1 N HCl for neutralisation. The percentage of Na₂CO₃ is approximately:

Equivalent Concept & Titrations(15 Qs)

easy (5)

Q1Equivalent weight of an acid is:Q2The indicator used in strong acid vs strong base titration is:Q3At the equivalence point of neutralization:Q4N₁V₁ = N₂V₂ is the equation for:Q5A standard solution is one whose ___ is accurately known:

medium (5)

Q125 mL of 0.1 M NaOH neutralises ___ mL of 0.1 M H₂SO₄:Q2The n-factor of KMnO₄ in acidic medium is:Q3Back titration is used when:Q4The n-factor of K₂Cr₂O₇ in acidic medium is:Q5Molality of a solution is defined as:

hard (5)

Q10.5 g of an oxalic acid sample requires 40 mL of 0.1N NaOH. The purity of oxalic acid (M = 126) is:Q2In iodometric titration, I₂ liberated is titrated with:Q3A solution contains 0.1 mol FeSO₄ and 0.1 mol Fe₂(SO₄)₃. Volume of 0.1M KMnO₄ in acidic medium needed to oxidize all Fe²⁺:Q4The number of millimoles present in 250 mL of 0.2 M solution is:Q5The normality of "10 volume" H₂O₂ solution is approximately:

More Chemistry Chapters

Atomic Structure

15 Qs

Chemical Thermodynamics

30 Qs

Chemical Equilibrium

15 Qs

Electrochemistry

15 Qs

Chemical Kinetics

15 Qs

Solutions

15 Qs

Need Help with Mole Concept & Stoichiometry?

Get 1-on-1 doubt sessions and personalised practice analysis with MindPeak's JEE mentors.

MindPeak InstituteMINDPEAK

Personalized 1-on-1 JEE & NEET Coaching — Transforming Aspirants into Achievers.

JEE Preparation

  • JEE Coaching
  • JEE Physics Preparation
  • JEE Chemistry Preparation
  • JEE Mathematics Preparation
  • JEE Rank Predictor

NEET Preparation

  • NEET Coaching
  • NEET Physics Preparation
  • NEET Chemistry Preparation
  • NEET Biology Preparation
  • NEET Rank Predictor

Other Exams

  • BITSAT Coaching
  • CUET Coaching
  • WBJEE Coaching
  • MHT-CET Coaching
  • KVPY Coaching
  • ISI Entrance Coaching
  • COMEDK Coaching
  • VITEEE Coaching

Practice & PYQs

  • JEE Practice Questions
  • JEE Previous Year Questions
  • NEET Practice Questions
  • NEET Previous Year Questions

Formula Sheets

  • JEE Physics Formulas
  • JEE Chemistry Formulas
  • JEE Maths Formulas
  • NEET Biology Formulas
  • NEET Physics Formulas
  • NEET Chemistry Formulas

Quick Links

  • Courses
  • Free Trial
  • Pricing
  • Study Plan
  • Blog
  • Contact
  • Kota Alternative
  • Online vs Offline

JEE Coaching by City

  • JEE Coaching in Bangalore
  • JEE Coaching in Chennai
  • JEE Coaching in Hyderabad
  • JEE Coaching in Kochi
  • JEE Coaching in Coimbatore
  • JEE Coaching in Visakhapatnam
  • JEE Coaching in Vijayawada
  • JEE Coaching in Mangalore
  • JEE Coaching in Delhi
  • JEE Coaching in Mumbai
  • Best JEE Coaching in India

NEET Coaching by City

  • NEET Coaching in Bangalore
  • NEET Coaching in Chennai
  • NEET Coaching in Hyderabad
  • NEET Coaching in Kochi
  • NEET Coaching in Coimbatore
  • NEET Coaching in Visakhapatnam
  • NEET Coaching in Vijayawada
  • NEET Coaching in Mangalore
  • NEET Coaching in Delhi
  • NEET Coaching in Mumbai

Compare Coaching

  • MindPeak vs Allen
  • MindPeak vs FIITJEE
  • MindPeak vs Physics Wallah
  • MindPeak vs Unacademy
  • MindPeak vs Vedantu
  • MindPeak vs Aakash
  • Online vs Offline Coaching
  • Batch vs Personal Coaching

Important Links

  • Home
  • JEE Coaching
  • NEET Coaching
  • BITSAT Coaching
  • CUET Coaching
  • Courses
  • Pricing
  • Free Trial
  • Kota Alternative
  • JEE Rank Predictor
  • NEET Rank Predictor
  • Blog
  • Contact
  • Terms & Conditions
  • Refund Policy
Terms & Conditions|Refund Policy

© 2026 MindPeak Institute. All rights reserved. JEE Chemistry Practice — Mole Concept & Stoichiometry — 30 Questions.

JEE Coaching — 1-on-1JEE Rank Predictor 2027JEE Physics: Mechanics GuideNEET Coaching — 1-on-1NEET Rank Predictor 2027NEET Bio: Digestion & AbsorptionAll CoursesPricing PlansBlog & TipsContact Us